I am puzzling out 8051 assembler by writing some simple c code, compiling, and looking at the assembly output.

This fragment puzzled me:

C language:
char idata id0;
id0 = 0xaa;

Generated this output:
MOV R0, #0x08 ; this is the address at which id0 is stored, OK
MOV @R0, #SADDR1(0xAA) ; what the #$%! is SADDR1?
;I gather this moves a literal to the address in r0 ...
;but I don't get the syntax. What's wrong with:
MOV @R0, #0xAA ; ???

SADDR1 is not in the book index ...

Eric