??? 05/23/07 21:00 Read: times |
#139694 - I would call this... Responding to: ???'s previous message |
... packed-BCD-to-binary conversion.
;input: packed BCD mov r0,a ;separate the high and low nibble first anl a,#0Fh xch a,r0 mov b,#10 ;the high nibble has to be multiplied by 10 mul ab add a,r0 ;now add accumulator Is this what you want? JW |
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