| ??? 10/18/07 22:16 Read: times |
#145925 - Definitely not 8051! Responding to: ???'s previous message |
Rodrigo Araujo said:
mov al, ascii ; for the first element in the string "12345..." mov ah, ascii+1; for the second element in the string"12345.." The 8051 is an 8-bit processor - it does not have AL and AH registers! sub al, 30h ; so i get the decimal and not the hex But that will only affect AL, won't it? What about the other character that you put into AH...? But my question is how i would store all the number in eax so i can use another PROC to make eax into a binary Again, there is no such thing as EAX on an 8051, so you are in the wrong forum for that question! But I think you should take another approach: Don't try to load all the characters at once - use a loop to process them one at a time... |
| Topic | Author | Date |
| ASCII to Binary in Assembly | 01/01/70 00:00 | |
| What guidance do you need? | 01/01/70 00:00 | |
| this might be part of the fun :-) | 01/01/70 00:00 | |
| Not 8051? | 01/01/70 00:00 | |
| Isn't a double 32 bits? | 01/01/70 00:00 | |
| I think so | 01/01/70 00:00 | |
| No, it's not correct | 01/01/70 00:00 | |
| No, that's wrong. | 01/01/70 00:00 | |
Thanks | 01/01/70 00:00 | |
| I'm here so far !! | 01/01/70 00:00 | |
| Definitely not 8051! | 01/01/70 00:00 | |
| you are on 8052.com... | 01/01/70 00:00 | |
| Sorry Andy | 01/01/70 00:00 | |
| Leg up | 01/01/70 00:00 | |
| I think i got it! may u check it? | 01/01/70 00:00 | |
| listen to your teacher | 01/01/70 00:00 | |
| Check | 01/01/70 00:00 | |
| Bonus question | 01/01/70 00:00 | |
| Lol | 01/01/70 00:00 |