| ??? 01/16/08 19:39 Read: times |
#149599 - if you remove the ISR and leave EA in, the uC will Responding to: ???'s previous message |
ES and EA are there because i started working on interrupt driven code but as that was not working i strip down the code
If you remove the ISR and leave ES in, the uC will go to lunch whenever the UART has finished processing a cha.r be that receive or transmit. Use CodeArchitect, free from http://www.esacademy.com if you do not like the code, at least you have a reference. Erik |
| Topic | Author | Date |
| Serial communication problem | 01/01/70 00:00 | |
| have you heard of formatting and comments? | 01/01/70 00:00 | |
| I am sorry about formatting | 01/01/70 00:00 | |
| if you remove the ISR and leave EA in, the uC will | 01/01/70 00:00 | |
| I removed ES = 1, still same result. | 01/01/70 00:00 | |
| How to post source code | 01/01/70 00:00 | |
| few more notes | 01/01/70 00:00 | |
| timing? | 01/01/70 00:00 | |
| Andy, read my post | 01/01/70 00:00 | |
I did! | 01/01/70 00:00 | |
| why are you screwing with the trim? | 01/01/70 00:00 | |
| Thanks everyone its was trim register | 01/01/70 00:00 | |
| Hello, World | 01/01/70 00:00 |