| ??? 12/02/08 12:01 Read: times |
#160495 - why "TI0=1;" is required Responding to: ???'s previous message |
Tsuneo Chinzei said:
But when you are handling the UART in interrupt, why "TI0=1;" is required at the initialization stage on the main()?
It evokes the UART interrupt uselessly. Keil's default (polled) putchar requires TI to be set "manually" to get things started (look at their "Hello, world" examples) - maybe it's a hangover from that...? |
| Topic | Author | Date |
| Program hangs at one point - 8051F340 | 01/01/70 00:00 | |
| Assembly window | 01/01/70 00:00 | |
| hyper terminal interface | 01/01/70 00:00 | |
| Stack size? | 01/01/70 00:00 | |
| Stack size | 01/01/70 00:00 | |
| Stack Management | 01/01/70 00:00 | |
| Watchdog | 01/01/70 00:00 | |
| stack and preview.. | 01/01/70 00:00 | |
| Limited stack | 01/01/70 00:00 | |
| Where is the UART ISR? | 01/01/70 00:00 | |
| ISR for UART | 01/01/70 00:00 | |
| ISR for UART? | 01/01/70 00:00 | |
| why "TI0=1;" is required | 01/01/70 00:00 | |
| No, it isn't | 01/01/70 00:00 | |
| Solved - I guess | 01/01/70 00:00 | |
| 'polling' is NOT "standard C" | 01/01/70 00:00 | |
| You are right Erik.. | 01/01/70 00:00 | |
Thought I will thank you individually.. | 01/01/70 00:00 | |
| Disable watchdog | 01/01/70 00:00 | |
| and in Keil it is: | 01/01/70 00:00 | |
| Status : WDT disabling in the status worked | 01/01/70 00:00 |