| ??? 03/20/09 12:09 Read: times |
#163687 - Idea Responding to: ???'s previous message |
Luis, as your teacher wants a software solution with level (no triggered interrupt) think in this way:
- at begining interrupt is active - a low level in input produces interrupt - the service routine disables the interrupt - interrupt makes its work... - executes a RETI - the main program (or some periodic interrupt: timer) checks the input and reenable interrupt when pin is high Daniel |
| Topic | Author | Date |
| Question of level triggered interrupt | 01/01/70 00:00 | |
| Edge Triggered Interrupt | 01/01/70 00:00 | |
| Only Level triggered | 01/01/70 00:00 | |
| It's not a "problem". | 01/01/70 00:00 | |
| the problem is not technical... | 01/01/70 00:00 | |
| Let me explain again | 01/01/70 00:00 | |
| Idea | 01/01/70 00:00 | |
| What the teacher wants... | 01/01/70 00:00 | |
| Several options... | 01/01/70 00:00 | |
| thats..... | 01/01/70 00:00 | |
| May be you missunderstud | 01/01/70 00:00 | |
| Use a while() trap | 01/01/70 00:00 | |
| Yeah | 01/01/70 00:00 | |
| Use a watchdog timer | 01/01/70 00:00 | |
| How about this? | 01/01/70 00:00 | |
| Wow | 01/01/70 00:00 | |
| which derivative has this feature ? | 01/01/70 00:00 | |
| Our friend the $ | 01/01/70 00:00 | |
Oooops | 01/01/70 00:00 | |
| Answer to my question | 01/01/70 00:00 | |
| Thought about | 01/01/70 00:00 |