Hi again...

I think my crystal Calculation is right:
For Timer 1:
256 - ( ( 24000000 / 384 ) / 31250 ) = 254
For Timer 2:
256 - ( ( 24000000 / 32 ) / 250000 ) = 253


Kai, there arent close enough value... its just the perfect value... luckly!

I could receive MIDI with no problem.

I think, my major problem now is sending DMX... I dont have a comercial DMX receiver device to test, so, I'm working blind.
I have a Kathy's DMX receiver mounted here... and works with it.
But, I'm in doubt if a comercial DMX device will work.

Some web pages says DMX have 2 start bits (or a start bit with 8mS) other says just one start bit (4 mS)
Two stop bits, would be really good if just waiting 4 mS after sending a byte solves.

Here is what I'm using to send the DMX, with 24mhz crystal and 8 bit serial:

RUN:
;
;...
;
        CLR TXD
        MOV TEMP,#190        ;Break
        DJNZ TEMP,$
        SETB TXD

        SETB TB8
        MOV SBUF,#0		;SC
        JNB TI,$
        CLR TI
        nop
        nop
        nop
        nop
        nop
        nop
        nop

        MOV R0,#127

BYTESLOOP:
        INC R0
        
        SETB TB8
        MOV SBUF,@R0
        JNB TI,$
        CLR TI
        nop
        nop
        nop
        nop
        nop
        nop
        nop
        
        CJNE R0,#255,BYTESLOOP
        
        JMP	RUN

 

I Think SETB TB8 does nothing when using 8bit serial, just forgot to remove, there's some problem?


Also, please, if someone could answer this, would be very instructive for me:
I never worked with dual baud rates, and duplex mode, how should I make the ISR routine? When should I clear TI and RI? In example, will have an interruption for TI while a RI interruption is running?
What happens when a TI ISR is running then a RI arrives (vice versa)?

There is some problem if during RI ISR I send a byte by serial (MOV Sbuf,...)? (being TX idle of course)


Thanks.