| ??? 03/03/00 08:47 Read: times |
#1666 - RE: help - 16 bit multiplication |
Hi Travis,
If you use the insruction MUL AB then MC multiplies the unsigned value of the Accumulator by the unsigned value of the "B" register. The least significant byte of the result is placed in the Accumulator and the most-significant-byte is placed in the "B" register. It is up to you how put it into the registers/memory. But the Intel rule sounds: put the low byte of the result into lowest memory and put the high byte into the high memory. All the best, George |
| Topic | Author | Date |
| help - 16 bit multiplication | 01/01/70 00:00 | |
| RE: help - 16 bit multiplication | 01/01/70 00:00 | |
| RE: help - 16 bit multiplication | 01/01/70 00:00 | |
RE: help - 16 bit multiplication | 01/01/70 00:00 |



