| ??? 11/23/01 11:06 Read: times |
#16853 - RE: 8bit- bin value to 3 bcd values... |
Simple:
mov a,binval ;a=value mov b, #064h ;b=100 div ab ;divide value by 100 mov r0,a ;hundreds digit is in r0 mov a,b ;remainder in a mov b,#0ah ;b=10 div ab ;divide by 10 mov r1,a ;tens digit is in r1 mov r2,b ;units digit is in r2 I don't think there's any simpler way of doing this :D Kundi |
| Topic | Author | Date |
| 8bit- bin value to 3 bcd values... | 01/01/70 00:00 | |
| RE: 8bit- bin value to 3 bcd values... | 01/01/70 00:00 | |
| ...and then I have to | 01/01/70 00:00 | |
| RE: ...and then I have to | 01/01/70 00:00 | |
| RE: ...and then I have to | 01/01/70 00:00 | |
How to switch hex16bit to packaged_BCD ? | 01/01/70 00:00 |



