| ??? 02/28/02 21:30 Read: times |
#20283 - RE: Basic Question on 13 and 16 bit timers |
Sean,
It really isn't too difficult: the timer/counter value is the concatenation of THx and TLx. In Mode 0 only 5 of the available bits in TLx are used, thus leaving us with 5+8 = 13 bits. In Mode 1 all 8 bits are used, so you have a 16-bit counter. Let's assume Timer mode is configured. TLx is incremented every machine cycle (12 oscillator cycles on a 'standard' 8051). It starts at zero and counts to 31. At the next cycle, two things happen: 1. TLx is reset to zero 2. THx is incremented The timer value can now be read as: 32*THx + TLx (in this case it's 32*1 + 0 = 32). The same applies to Mode 1, except that TLx counts to 255 before it overflows and THx is incremented. Hope this clarified things a bit. Best regards, Rob Klein. |
| Topic | Author | Date |
| Basic Question on 13 and 16 bit timers | 01/01/70 00:00 | |
| RE: Basic Question on 13 and 16 bit timers | 01/01/70 00:00 | |
| RE: Basic Question on 13 and 16 bit timers | 01/01/70 00:00 | |
| RE: Basic Question on 13 and 16 bit timers | 01/01/70 00:00 | |
| RE: Basic Question on 13 and 16 bit timers | 01/01/70 00:00 | |
| RE: Basic Question on 13 and 16 bit timers | 01/01/70 00:00 | |
RE: Basic Question on 13 and 16 bit timers | 01/01/70 00:00 |



