| ??? 11/18/02 20:55 Read: times |
#32707 - RE: calculus by assembly |
probably by going back to basics:
Differentiation involves finding a rate of change, or gradient, dx/dy; so you'd probably sample x at two points an interval dy apart and compute the gradient from there. Integration involves summing a quantity over a period (not necessarily time). |
| Topic | Author | Date |
| calculus by assembly | 01/01/70 00:00 | |
| RE: calculus by assembly | 01/01/70 00:00 | |
| RE: calculus by assembly | 01/01/70 00:00 | |
| RE: calculus by assembly | 01/01/70 00:00 | |
| RE: calculus by assembly | 01/01/70 00:00 | |
| RE: calculus by assembly | 01/01/70 00:00 | |
| RE: calculus by assembly | 01/01/70 00:00 | |
| RE: calculus by assembly | 01/01/70 00:00 | |
| RE: Integrating | 01/01/70 00:00 | |
| RE: calculus by assembly | 01/01/70 00:00 | |
| RE: calculus by assembly | 01/01/70 00:00 | |
| RE: calculus by assembly | 01/01/70 00:00 | |
| RE: calculus by assembly | 01/01/70 00:00 | |
| RE: calculus by assembly | 01/01/70 00:00 | |
| IMRAN IDREES - where are you?? | 01/01/70 00:00 | |
| RE: calculus by assembly | 01/01/70 00:00 | |
RE: calculus by assembly | 01/01/70 00:00 |



