Email: Password: Remember Me | Create Account (Free)

Back to Subject List

Old thread has been locked -- no new posts accepted in this thread
???
11/18/02 20:55
Read: times


 
#32707 - RE: calculus by assembly
probably by going back to basics:

Differentiation involves finding a rate of change, or gradient, dx/dy; so you'd probably sample x at two points an interval dy apart and compute the gradient from there.

Integration involves summing a quantity over a period (not necessarily time).

List of 17 messages in thread
TopicAuthorDate
calculus by assembly            01/01/70 00:00      
RE: calculus by assembly            01/01/70 00:00      
RE: calculus by assembly            01/01/70 00:00      
RE: calculus by assembly            01/01/70 00:00      
RE: calculus by assembly            01/01/70 00:00      
RE: calculus by assembly            01/01/70 00:00      
RE: calculus by assembly            01/01/70 00:00      
RE: calculus by assembly            01/01/70 00:00      
RE: Integrating            01/01/70 00:00      
RE: calculus by assembly            01/01/70 00:00      
RE: calculus by assembly            01/01/70 00:00      
RE: calculus by assembly            01/01/70 00:00      
RE: calculus by assembly            01/01/70 00:00      
RE: calculus by assembly            01/01/70 00:00      
IMRAN IDREES - where are you??            01/01/70 00:00      
RE: calculus by assembly            01/01/70 00:00      
RE: calculus by assembly            01/01/70 00:00      

Back to Subject List