Do the same with 16 or 32 math routines

Pseudocode:

(Number / 10000000)+30h = 1st ascii char
(Rest / 1000000)+30h = 2nd ascii char
(Rest / 100000)+30h = 3rd ascii char
(Rest / 10000)+30h = 4th ascii char
(Rest / 1000)+30h = 5th ascii char
(Rest / 100)+30h = 6th ascii char
(Rest / 10)+30h = 7th ascii char
rest + 30h are the 8th ascii char (units)