| ??? 01/08/03 23:07 Read: times |
#35979 - RE: 12-bit adc - Mike |
Dividing each sample like that by two before adding is next to worthless.
If you look at it carefully, you will see that it employ a technique to keep 16 bit values within 16 bits. That, of course, has no purpose with 16 samples of 12 bits. Just wanted to point out why (at least I think so) thet particular method was used. Erik |
| Topic | Author | Date |
| 12-bit adc | 01/01/70 00:00 | |
| RE: 12-bit adc | 01/01/70 00:00 | |
| RE: 12-bit adc | 01/01/70 00:00 | |
| RE: 12-bit adc | 01/01/70 00:00 | |
| RE: 12-bit adc | 01/01/70 00:00 | |
| RE: 12-bit adc | 01/01/70 00:00 | |
| RE: 12-bit adc | 01/01/70 00:00 | |
| RE: 12-bit adc - Mike | 01/01/70 00:00 | |
| RE: 12-bit adc - Mike | 01/01/70 00:00 | |
| RE: 12-bit adc - Erik / Steve | 01/01/70 00:00 | |
| RE: 12-bit adc - Erik / Steve | 01/01/70 00:00 | |
| RE: 12-bit adc | 01/01/70 00:00 | |
| RE: 12-bit adc / Rob | 01/01/70 00:00 | |
| RE: 12-bit adc / Rob | 01/01/70 00:00 | |
| RE: 12-bit adc / Rob | 01/01/70 00:00 | |
RE: 12-bit adc / Rob | 01/01/70 00:00 |



