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01/08/03 23:07
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#35979 - RE: 12-bit adc - Mike
Dividing each sample like that by two before adding is next to worthless.
If you look at it carefully, you will see that it employ a technique to keep 16 bit values within 16 bits. That, of course, has no purpose with 16 samples of 12 bits.

Just wanted to point out why (at least I think so) thet particular method was used.

Erik


List of 16 messages in thread
TopicAuthorDate
12-bit adc            01/01/70 00:00      
RE: 12-bit adc            01/01/70 00:00      
RE: 12-bit adc            01/01/70 00:00      
RE: 12-bit adc            01/01/70 00:00      
RE: 12-bit adc            01/01/70 00:00      
RE: 12-bit adc            01/01/70 00:00      
RE: 12-bit adc            01/01/70 00:00      
RE: 12-bit adc - Mike            01/01/70 00:00      
RE: 12-bit adc - Mike            01/01/70 00:00      
RE: 12-bit adc - Erik / Steve            01/01/70 00:00      
RE: 12-bit adc - Erik / Steve            01/01/70 00:00      
RE: 12-bit adc            01/01/70 00:00      
RE: 12-bit adc / Rob            01/01/70 00:00      
RE: 12-bit adc / Rob            01/01/70 00:00      
RE: 12-bit adc / Rob            01/01/70 00:00      
RE: 12-bit adc / Rob            01/01/70 00:00      

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