| ??? 02/21/03 09:23 Read: times |
#39628 - RE: Linear Voltage to Current conversion... Responding to: ???'s previous message |
If you used two resistors to divide the input voltage by a factor of ten before feeding the pin3, you could use a 5R sense resistor. This would only dissipate 50mW so you can use a normal resistor. You can now also use a low supply voltage again for the opamp (assuming you use a logic level fet and a R2R opamp)
Igor |
| Topic | Author | Date |
| Linear Voltage to Current conversion... | 01/01/70 00:00 | |
| RE: Linear Voltage to Current conversion... | 01/01/70 00:00 | |
| RE: Linear Voltage to Current conversion... | 01/01/70 00:00 | |
| RE: Linear Voltage to Current conversion... | 01/01/70 00:00 | |
| RE: Linear Voltage to Current conversion... | 01/01/70 00:00 | |
| RE: Linear Voltage to Current conversion... | 01/01/70 00:00 | |
| RE: Linear Voltage to Current conversion | 01/01/70 00:00 | |
| RE: PWM to Current conversion... | 01/01/70 00:00 | |
RE: PWM to Current conversion... | 01/01/70 00:00 | |
| RE: Linear Voltage to Current conversion... | 01/01/70 00:00 |



