| ??? 07/08/03 10:20 Read: times |
#50265 - RE: square root Responding to: ???'s previous message |
hi,
please correct the equation. puting the value of f(x) and f'(x) gives following xn+1 = xn - (xn^2-a)/2xn this equation can can be more simplified and suitable for programming. abhishek |
| Topic | Author | Date |
| square root | 01/01/70 00:00 | |
| RE: square root | 01/01/70 00:00 | |
| RE: square root | 01/01/70 00:00 | |
| RE: square root | 01/01/70 00:00 | |
| RE: square root | 01/01/70 00:00 | |
| RE: square root | 01/01/70 00:00 | |
| RE: square root | 01/01/70 00:00 | |
| RE: square root | 01/01/70 00:00 | |
RE: square root | 01/01/70 00:00 |