Hi Alberto,

When you compile a program normally, the compiler assumes the normal configuration with boot and interrupt vectors starting at 0x0000, then startup code and finally the code you have written.

To get your code to run at 0x8000 you are going to have to tell the compiler and linker to start it at 0x8000, and you're still going to have to deal with the interrupt vectors which are still at 0x0000 (since the hardware defines those addresses).

Is this new code supposed to coexist with the original code? If so, when an interrupt occurs, is an ISR in the original or new code called?

Do a search here; someone else was working on the exact same problem not too long ago.

Dennis