| ??? 12/01/03 21:06 Read: times |
#59731 - RE:I\\\'m confused Responding to: ???'s previous message |
The 128 bit of bit space cover the address range of 20h...27h, which is 8bit x 8bytes = 128bit wide. I thought 8 x 8 =64. 128 bit space could be 2f hex - 20 hex = f hex, convert to decimal = 16, therfore 16 * 8 = 128 bits. Joe |
| Topic | Author | Date |
| Bit Memory | 01/01/70 00:00 | |
| RE: Bit Memory | 01/01/70 00:00 | |
| RE: Bit Memory | 01/01/70 00:00 | |
| RE:I\\\'m confused | 01/01/70 00:00 | |
| RE: clearing the confoosion | 01/01/70 00:00 | |
| RE: I'm confused | 01/01/70 00:00 | |
| RE: Bit Memory | 01/01/70 00:00 | |
| RE: Bit Memory | 01/01/70 00:00 | |
RE: Bit Memory | 01/01/70 00:00 |