Mr Raghu,I use crystal 11,0592Mhz.
I want to complete your example :

MOV P0.0,#00H
START : MOV R2,#08H ;COUNTER 8 BIT
INPUT : MOV C,P0.0
MOV ACC.0,C
MOV B,ACC
RL A
DJNZ R2,INPUT
MOV ACC,B
PUSH ACC
JMP START
END

if input high in P0.0 during 2 second, how many data bit will be save in accumulator or internal memory ( after push instruction) ?
Thank