Here is another way that is not so direct but does nearly the same thing. In this case presume that you are using the default register bank #0 where Register 1 is at internal RAM address 1 and Register 2 is at internal RAM address 2.

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     CLR    A            ; initial clear A
     MOV    R0, #2       ; indirect pointer to R2
     XCH    A, @R0       ; get R2 byte to A
     DEC    R0           ; indirect pointer to R1
     XCHD   A, @R0       ; swap low nibble of R1 into A

Michael Karas