| ??? 11/24/04 15:41 Read: times |
#81857 - Notation Responding to: ???'s previous message |
Hi
I have already used sprint().sprintf converts the value of double (in which i have the result) into the char buffer. But my problem is how can i convert 9.801E+07 into 98010000. Regards Farhan |
| Topic | Author | Date |
| Scientific notation to normal notation | 01/01/70 00:00 | |
| " | 01/01/70 00:00 | |
| Notation | 01/01/70 00:00 | |
| is this float to long? | 01/01/70 00:00 | |
| Format | 01/01/70 00:00 | |
| Ooops | 01/01/70 00:00 | |
| sprintf | 01/01/70 00:00 | |
| Time for clarification | 01/01/70 00:00 | |
| " | 01/01/70 00:00 | |
| Sprintf | 01/01/70 00:00 | |
| " | 01/01/70 00:00 | |
| " | 01/01/70 00:00 | |
| WYGIWYAF | 01/01/70 00:00 | |
| Hi | 01/01/70 00:00 | |
| notation problem | 01/01/70 00:00 | |
| try sprintf(buffer,"%f",result); | 01/01/70 00:00 | |
| New habits | 01/01/70 00:00 | |
Exactly what it says on the tin! | 01/01/70 00:00 |