| ??? 01/15/01 06:02 Read: times |
#8214 - RE: Volt=(165/255)*17.5 |
Hi Dave,
There is no need to do that in floating point! Do you know how to divide and multiply binary? If you do you know all there is to know. I bet you don't need 10 decimals accuracy, so fixed point calculations will do just as well. To give you a small hint. Multiplying with 17.5 is exactly the same as mulitplying with 35 and then divide by 2, which is shifting the number 1 bit to the right. Good luck |
| Topic | Author | Date |
| Volt=(165/255)*17.5 | 01/01/70 00:00 | |
| RE: Volt=(165/255)*17.5 | 01/01/70 00:00 | |
| RE: Volt=(165/255)*17.5 | 01/01/70 00:00 | |
| RE: Volt=(165/255)*17.5 | 01/01/70 00:00 | |
| RE: Volt=(165/255)*17.5 | 01/01/70 00:00 | |
| RE: Volt=(165/255)*17.5 | 01/01/70 00:00 | |
| RE: Volt=(165/255)*17.5 | 01/01/70 00:00 | |
RE: Volt=(165/255)*17.5 | 01/01/70 00:00 |



