??? 03/18/05 13:14 Read: times |
#89934 - solution Responding to: ???'s previous message |
Harish 7FFF in binary is 0111 1111 1111 1111 8000 in binary is 1000 0000 0000 0000 then for 0000 to 7fff the MSB bit is zero and for 8000 to ffff the msb bit is one take the MSB put in an input of an nand gate, and the other input to zero logic then put input and output to a poles of DPDT switch and the poles switched to CS of the eprom and ram in –> nand -> dpdt (pole 1 and 4) in -> dpdt (pole 2 and 3) dpdt (pole 5 –out-) to CS ram dpdt (pole 6 –out-) to CS eprom then you can select easily what range is asigned sorry for my english. Regards, Ricardo |
Topic | Author | Date |
Interfacing to EPROM/RAM | 01/01/70 00:00 | |
Yes you can...but | 01/01/70 00:00 | |
do some reading on how the 8051 works | 01/01/70 00:00 | |
exact hardware | 01/01/70 00:00 | |
Yes but.... | 01/01/70 00:00 | |
its mentioned | 01/01/70 00:00 | |
Actually it isn't | 01/01/70 00:00 | |
sorry for that | 01/01/70 00:00 | |
xor | 01/01/70 00:00 | |
truth table | 01/01/70 00:00 | |
solution![]() | 01/01/70 00:00 |