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???
08/15/05 12:42
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#99418 - Answer
Responding to: ???'s previous message
James said:
I know the formula to calculate a low pass filter and given C=100nf how would I calculate the value of R given your proposed circuit if I wished my cutoff frequency to be 15khz.
Because there are other resistors in series with the input I am not sure which resistors would figure in the calculations. I would think only one of the 5.1k resistors would need to be figured into the equation.

The filter is meant to eliminate fast spikes and HF-noise being superimposed on Vcc = 3V. So, look at the components being connected to Vcc = 3V. Now, cut this connection, insert a 100Ohm resistor and connect a 100nF capacitor from this connection point to ground.
Corner frequency of this low pass filter is

fc = 1 / (2 x pi x R x C) = 15.9kHz

Kai

List of 18 messages in thread
TopicAuthorDate
LPC9xx Comparators and Hysterisis            01/01/70 00:00      
   Feedback resistor is not enough            01/01/70 00:00      
      Is this allright            01/01/70 00:00      
         Tested it.            01/01/70 00:00      
         calculations            01/01/70 00:00      
            Re: Calculations.            01/01/70 00:00      
               step down rartio            01/01/70 00:00      
         Values need a change            01/01/70 00:00      
            Please show the analyses            01/01/70 00:00      
            Re: Value Changes.            01/01/70 00:00      
               my doubt is            01/01/70 00:00      
               Answers            01/01/70 00:00      
                  1N914 not Zener.            01/01/70 00:00      
                     Silent at many places            01/01/70 00:00      
            Low pass filter            01/01/70 00:00      
               Answer            01/01/70 00:00      
   Zero crossing detection            01/01/70 00:00      
   Thanks            01/01/70 00:00      

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