| ??? 09/16/05 09:07 Read: times |
#101156 - atomic not possible in general ! Responding to: ???'s previous message |
Oleg Sergeev said:
That`s correct but what if all bits must be changed simultaneously? Its only one cycle (1µs at 12MHz) delayed, so it should play no role in almost all cases. Especially since the low to high and high to low transition times are not equal in general. Maybe on a certain capacitive load it can be equal on my code, since the first high driving was not so strong as the later low driving. In other words, also a direct mov to a port cause different transition times. So any design which count on an equal transition time was a very bad design and should fail at all. Peter |
| Topic | Author | Date |
| Week puzzle IV | 01/01/70 00:00 | |
| In my opinion | 01/01/70 00:00 | |
| no | 01/01/70 00:00 | |
| Bufff!! then TRB | 01/01/70 00:00 | |
| Me and my shadow, walking down the aven | 01/01/70 00:00 | |
| You & your shadow | 01/01/70 00:00 | |
| http://www.coleporter.org/ | 01/01/70 00:00 | |
| it's a hint | 01/01/70 00:00 | |
| Well | 01/01/70 00:00 | |
| you got it | 01/01/70 00:00 | |
| Just OR with ones | 01/01/70 00:00 | |
| how? | 01/01/70 00:00 | |
| a simple solution: | 01/01/70 00:00 | |
| not atomic | 01/01/70 00:00 | |
atomic not possible in general ! | 01/01/70 00:00 | |
| My solution! | 01/01/70 00:00 | |
| Wrong | 01/01/70 00:00 | |
| not atomic | 01/01/70 00:00 | |
| Ok, here is the shadow | 01/01/70 00:00 | |
| only four bits | 01/01/70 00:00 | |
| 2 Hints! | 01/01/70 00:00 | |
| Oh boy, do you need some bible time | 01/01/70 00:00 | |
| re: 2 Hints! | 01/01/70 00:00 |