| ??? 10/25/05 15:25 Read: times |
#102923 - I dont get it :( Responding to: ???'s previous message |
As far as i knew ,I/O lines have to change their state somewhere between the system clocks(Not cycles) So if we have a faster clock , our I/O have to change its state with a faster Rise time .
i can't understand your point very well , so lets make an example. look at this code : Loop: Setb p1.0 sjmp loop The above instructions should produce a 500 khz (12 Mhz crystal on a 12 clocker) signal.are you saying that increasing the crystal frequency to 24Mhz would produce a 1Mhz signal on the P!.0 with the same rise time as we had with the 12 Mhz crystal ? Farshid |
| Topic | Author | Date |
| 22 MHZ ISP | 01/01/70 00:00 | |
| Datasheet | 01/01/70 00:00 | |
| 4-24 Mhz | 01/01/70 00:00 | |
| not really | 01/01/70 00:00 | |
| Rise Time | 01/01/70 00:00 | |
| sure, but that does not change the riset | 01/01/70 00:00 | |
| I dont get it :( | 01/01/70 00:00 | |
| yes | 01/01/70 00:00 | |
Constant rise time | 01/01/70 00:00 |