??? 08/25/08 12:26 Read: times |
#157737 - One tip Responding to: ???'s previous message |
Dear Priyam,
You have written EA = 1; EX0 = 1; EX1 = 1 inside an while(1). This is not necessary if you are not clearing bits anywhere. Take it out side(before entering while(1)). If you need to glow led only when INTx is low, you can do something like following. // this code is for compiling using SDCC void ex0_isr (void) interrupt 0 _naked { switch led on while(!(P3_2)); //wait till low level switch off the led } Note: _naked works for SDCC, it tells SDCC that whatever push-pop etc is required will be done by programmer(hence compiler will compile your code only) Regards, Mahesh |
Topic | Author | Date |
pls help....8051 external interrupts | 01/01/70 00:00 | |
show definition of "a" variable | 01/01/70 00:00 | |
definiton : sbit a=P3^2; | 01/01/70 00:00 | |
Need more information | 01/01/70 00:00 | |
the entire code | 01/01/70 00:00 | |
keyscan | 01/01/70 00:00 | |
How the LED are connected? | 01/01/70 00:00 | |
One tip | 01/01/70 00:00 | |
P3.2= iNT0 | 01/01/70 00:00 | |
P3.2= INT0 | 01/01/70 00:00 | |
pin 3.2 | 01/01/70 00:00 | |
P3.2= INT0..1 | 01/01/70 00:00 | |
Obvious Reason | 01/01/70 00:00 | |
time duration | 01/01/70 00:00 | |
mistake | 01/01/70 00:00 | |
ok thanks alot | 01/01/70 00:00 | |
? | 01/01/70 00:00 | |
GATE0/1 ? | 01/01/70 00:00 | |
no | 01/01/70 00:00 | |
try | 01/01/70 00:00 | |
Debounce maybe? | 01/01/70 00:00 | |
Solution | 01/01/70 00:00 | |
interrupt flag bit clear | 01/01/70 00:00 | |
Detecting Both Edges - A very old trick![]() | 01/01/70 00:00 |