Erik I GOT IT!

It was this:
ES = 1; // enable UART interrupt

I had it in my initialization routine, but I did not have this:

void UART(void) interrupt 4 //Interrupt number for serial port
{
RI = 0; // clear receive interrupt flag
}

So it was causing an error. Now I have it all included and just to double check it I put two traps in the program and it is shifting, LED = 1 and generating an interrupt, like I wanted to. I know it is doing the interrupt because as soon as it enters it, the LED = 0 and P2 does something else...jajaja
Got it!
Thanks Erik. You are always helpful.
If you want you can errase this thread
J.C.