| ??? 05/07/07 17:53 Read: times |
#138734 - Spoofing 2 stop bits? |
Okay, so I skipped a few steps in Mr. Cooper's syllabus and got the chip "echoing" characters nicely. My problem now is that I must talk to a device which expects two stop bits, and the data sheet, programmer's guide, "bible" make no mention of this capability. I've tried setting the ninth data bit both high and low, in hopes of emulating the first stop bit. That didn't work.
I've heard tell of "bit-banging" which would seem to a) solve this issue perfectly and b) not leave a lot of CPU time for other tasks. Is there a standard solution to this? Many Thanks, Bob Robertson |
| Topic | Author | Date |
| Spoofing 2 stop bits? | 01/01/70 00:00 | |
| tghere is no such thing as 2 stop bits | 01/01/70 00:00 | |
| Inidistinguishable | 01/01/70 00:00 | |
| Some UARTs of yesteryear supported it! | 01/01/70 00:00 | |
| Yesteryear? | 01/01/70 00:00 | |
| question? | 01/01/70 00:00 | |
| 9N1=8N2! | 01/01/70 00:00 | |
| That's what I thought! | 01/01/70 00:00 | |
| code - or comment - wrong | 01/01/70 00:00 | |
| just lazy commenting, sorry n/t | 01/01/70 00:00 | |
| I repeat | 01/01/70 00:00 | |
| stopbit = 1! | 01/01/70 00:00 | |
| 1!1!!!1 | 01/01/70 00:00 | |
| what exactly... | 01/01/70 00:00 | |
| Resolved | 01/01/70 00:00 | |
RTFM, or WTFM? | 01/01/70 00:00 |