| ??? 05/08/07 14:59 Read: times |
#138841 - stopbit = 1! Responding to: ???'s previous message |
TB8=0;//set programmable 9th data bit so it's a stop bit Certainly not. Stopbit is 1. If you use 0 as 9th bit, the receiver might "perceive" it it as a false startbit (most of the '51 receivers don't check for stopbit properly). That's why you receive garbage. JW |
| Topic | Author | Date |
| Spoofing 2 stop bits? | 01/01/70 00:00 | |
| tghere is no such thing as 2 stop bits | 01/01/70 00:00 | |
| Inidistinguishable | 01/01/70 00:00 | |
| Some UARTs of yesteryear supported it! | 01/01/70 00:00 | |
| Yesteryear? | 01/01/70 00:00 | |
| question? | 01/01/70 00:00 | |
| 9N1=8N2! | 01/01/70 00:00 | |
| That's what I thought! | 01/01/70 00:00 | |
| code - or comment - wrong | 01/01/70 00:00 | |
| just lazy commenting, sorry n/t | 01/01/70 00:00 | |
| I repeat | 01/01/70 00:00 | |
| stopbit = 1! | 01/01/70 00:00 | |
| 1!1!!!1 | 01/01/70 00:00 | |
| what exactly... | 01/01/70 00:00 | |
| Resolved | 01/01/70 00:00 | |
RTFM, or WTFM? | 01/01/70 00:00 |