| ??? 08/02/07 13:33 Read: times |
#142651 - maths problem Responding to: ???'s previous message |
So, for (a crude) example, if your application is now roughly 16kB and the bootloader another 16kB, leave 16kB for each interrupt
I have a maths problem with your statement here, can you explain how to make this work? app 16kb IE0 16kb T0 16kb IE1 16kb T3 16kb T4 16kb UART0 16kb UART1 16kb IIC 16kb CAN 16kb boot 16kb ----------- = 64kbErik |
| Topic | Author | Date |
| an attempt at a failsave bootloader | 01/01/70 00:00 | |
| do you REALLY need that 1kB? | 01/01/70 00:00 | |
| I'll have to think on that one - excellent idea | 01/01/70 00:00 | |
| Flash uncertainty | 01/01/70 00:00 | |
| I did not consider | 01/01/70 00:00 | |
| extra jump and enough power | 01/01/70 00:00 | |
| extra junp | 01/01/70 00:00 | |
| no magic idea... | 01/01/70 00:00 | |
| maths problem | 01/01/70 00:00 | |
| I am absolutely sure... | 01/01/70 00:00 | |
| the penalty of an extra ljmp... | 01/01/70 00:00 | |
| Dont ReWrite Page 0 | 01/01/70 00:00 | |
not a PC ... | 01/01/70 00:00 |