| ??? 12/24/02 03:10 Read: times |
#34927 - RE: 32-bit Divide with Fixed Divisor |
Thanks everyone for the help...I think I'll follow Andy's advice of (1)first shifting right to divide by 64 (storing the 6 digits shifted out), (2) divide that value by 9375 to get the quotient and multiply the remainder of the second division by 64 and add it to the 6 digits shifted out to get the actual remainder. :)
Thanks again. |



