| ??? 09/24/04 06:36 Read: times Msg Score: +1 +1 Good Answer/Helpful |
#78052 - RE: You lose nothing ! Responding to: ???'s previous message |
on the otherhands, if i use a sign op-amp, convert the data to -2.5~2.5 data. (11bit + sign) It's not true that if you are in -/+ range you get "only" 11 bits. The sign is the twelfth bit ! As we know, the highest bit of the result tells if you are in lower (0) or higher (1) half of the measuring range. The -/+ signal is divided in two halfs - postive and negative, so the sign is just the highest bit, the result is equally accurate. Regards, Slobodan |
| Topic | Author | Date |
| ADC data problem | 01/01/70 00:00 | |
| RE: ADC data problem | 01/01/70 00:00 | |
| RE: ADC data problem | 01/01/70 00:00 | |
| OH, just thought of it | 01/01/70 00:00 | |
| RE: OH, just thought of it | 01/01/70 00:00 | |
| RE: ADC data problem | 01/01/70 00:00 | |
| RE: ADC data problem | 01/01/70 00:00 | |
| RE: ADC data problem | 01/01/70 00:00 | |
RE: You lose nothing ! | 01/01/70 00:00 |