| ??? 12/23/04 10:09 Read: times |
#83688 - Linear operation Responding to: ???'s previous message |
Robert Revens said:
... that resistor (which, thanks to Charles' link I now know moves the output from the crystal into the linear range). Note that it is the inverter that is put into its linear operating range; not the crystal. An inverter is essentially just a very, very high gain amplifier; so high that its output is usually clipping hard up at the +ve supply, or right down at ground. But there is still a linear amplifier region in between - and that's what's required in this application! (and this is why it tells you not to use a schmidt trigger inverter) |
| Topic | Author | Date |
| A little O/T help with UART Crystal | 01/01/70 00:00 | |
| Rethink | 01/01/70 00:00 | |
| Using current limiting resistor? | 01/01/70 00:00 | |
| Track cuts x200 | 01/01/70 00:00 | |
| I see no way | 01/01/70 00:00 | |
| full chip numbers | 01/01/70 00:00 | |
| Rp is missing with TI's chip! | 01/01/70 00:00 | |
| Thanks Kai | 01/01/70 00:00 | |
| Linear operation | 01/01/70 00:00 | |
| Resolution - I think..... | 01/01/70 00:00 | |
| Part Numbers | 01/01/70 00:00 | |
| the resistor | 01/01/70 00:00 | |
Both: Limiting and phase shifting | 01/01/70 00:00 | |
| Crystal oscillator reference. | 01/01/70 00:00 | |
| Thanks. | 01/01/70 00:00 |