??? 01/10/05 21:57 Read: times Msg Score: +1 +1 Good Answer/Helpful |
#84696 - Heat Transfer Rates and Efficiency Responding to: ???'s previous message |
Steve,
Based on some of the info in previous posts of this thread, I've got following numbers - A 600 gram block of copper raised cooled from 40 deg C to -40 deg C needs to get rid of 4.5 kcal. One kcal = 4187 watt-sec, so 70 watt cooler (100 % efficient) can cool the copper in about 4 and a half minutes. That's not far off the 7 minute number you measured going full tilt when it's recognized a Peltier is notoriously inefficient (and gets worse with increasing delta T). I'd say you've hit the minimum settling time. Bruce |
Topic | Author | Date |
OT Step responses | 01/01/70 00:00 | |
Step respons | 01/01/70 00:00 | |
Happy with PID | 01/01/70 00:00 | |
Re Happy with PID | 01/01/70 00:00 | |
more details | 01/01/70 00:00 | |
Making Use of Three Sensors | 01/01/70 00:00 | |
Heat pipe? | 01/01/70 00:00 | |
Minimizing Settling Time | 01/01/70 00:00 | |
Timing | 01/01/70 00:00 | |
Heat Transfer Rates and Efficiency | 01/01/70 00:00 | |
Nice estimation | 01/01/70 00:00 | |
Worked that out | 01/01/70 00:00 | |
Segments of different PID parameters | 01/01/70 00:00 | |
integrating cap | 01/01/70 00:00 | |
Abruptly changing... | 01/01/70 00:00 | |
Exaclty | 01/01/70 00:00 | |
Have you Read Above? | 01/01/70 00:00 | |
Sorry | 01/01/70 00:00 | |
Maybe this can help? | 01/01/70 00:00 | |
Interesting | 01/01/70 00:00 | |
Reference | 01/01/70 00:00 | |
RE: Reference![]() | 01/01/70 00:00 |