??? 05/25/05 17:24 Read: times |
#93898 - Looks the same to me Responding to: ???'s previous message |
Donald Catto said:
"Neil's point is that, although pointers & arrays are different, they both use the same Notation."
No. He states that "pointer notation and array notation are interchangeable". He does not state that "[pointers and arrays] use the same notation", which is even less correct, if it is possible to have a state of 'less correct'. By "Notation," I'm thinking of: void main( void ) { char my_array[] = "Array"; char *my_pointer = "Pointer"; char my_char; my_char = my_array[0]; my_char = my_pointer[0]; my_char = *my_array; my_char = *my_pointer; } The differences lie in the behaviour: |
Topic | Author | Date |
Unions in C | 01/01/70 00:00 | |
You miss the point completely... | 01/01/70 00:00 | |
Easy with Union | 01/01/70 00:00 | |
You can see from the Raghu example... | 01/01/70 00:00 | |
Platform-dependence | 01/01/70 00:00 | |
Padding in unions | 01/01/70 00:00 | |
portability | 01/01/70 00:00 | |
array=pointer...? | 01/01/70 00:00 | |
array != pointer | 01/01/70 00:00 | |
Quirk of C | 01/01/70 00:00 | |
Read the FAQ | 01/01/70 00:00 | |
Read the Comment | 01/01/70 00:00 | |
Read everything | 01/01/70 00:00 | |
Looks the same to me | 01/01/70 00:00 | |
This One | 01/01/70 00:00 | |
That's the problem | 01/01/70 00:00 | |
Good example | 01/01/70 00:00 | |
No fun | 01/01/70 00:00 | |
Well... | 01/01/70 00:00 | |
Of course it does! | 01/01/70 00:00 | |
Hmm | 01/01/70 00:00 | |
Actually, even less. | 01/01/70 00:00 | |
const pointer | 01/01/70 00:00 | |
O.K you win | 01/01/70 00:00 | |
Please conclude | 01/01/70 00:00 | |
Not Exactly | 01/01/70 00:00 | |
End of wrong stick?![]() | 01/01/70 00:00 |