It's always noted (where applicable) that Array notation is equivalent to const pointer. That is, you can't assign to the pointer, only to the object pointed to. So it seems only the allocation rule applies here.

void main( void )
{
    char  my_array[] = "Array";
    const char *my_pointer = "Pointer";

...

This way my_array=my_pointer; is just as illegal as my_pointer=my_array;.

Actually, there is at least one more quirk (according to FAQ). In 2- and more-dimensional arrays, types will differ and may conflict.

void main( void )
{
    char  my_array[2][2] = ("A","B");
    char** my_pointer;

    my_pointer=my_array; 
    /* type conflict, my_array works as pointer-to-array, 
     not pointer-to-pointer. */
}