| ??? 10/05/07 15:41 Read: times |
#145477 - I'm still certain Responding to: ???'s previous message |
that what you see would be the exact same if you just kept the priority at 3.
I do not doubt you statement "it works" (how could I, I do not have the thingy) I just am certain that (again if Atmel did not screw up) the reason "it works" is that you do not get held up by another interrupt when two interrupts are to be serviced immediately after each other. You can not (again if Atmel did not screw up) invoke another call to the same ISR while in it, you can, however, request the ISR to be serviced again while in it. Are your conclusions based on what you see in an ICE or is it "it works, so it must bhe because..." Erik |
| Topic | Author | Date |
| I tested changing prio level from the IT, it works | 01/01/70 00:00 | |
| you MUST be wrong | 01/01/70 00:00 | |
| For Erik | 01/01/70 00:00 | |
| redefine test | 01/01/70 00:00 | |
| what??? and comments | 01/01/70 00:00 | |
| what | 01/01/70 00:00 | |
| IT in derivatives | 01/01/70 00:00 | |
| Stored edges | 01/01/70 00:00 | |
| I'm still certain | 01/01/70 00:00 | |
| I don't see well what you mean. | 01/01/70 00:00 | |
| how about an answer | 01/01/70 00:00 | |
| you are right | 01/01/70 00:00 | |
just read \"the bible\" | 01/01/70 00:00 |