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???
01/16/08 14:31
Modified:
  01/16/08 14:34

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#149560 - Answers to Cooper
Responding to: ???'s previous message
Thanks for helping me clarify

I sort of doubt if you need to get into spherical geometry. Here are some questions to help answer that question for sure:
What is the maximum distance from you to any one of the ten stationary objects? In other words, how far does the telemtry work?
If you are only talking about short distances, then you can probably approximate the earth's surface as a plane.

The telemetry works from 4-6 Km , the receiver has a Yagi. I take your point to approximate the earth as plane.
Does that mean to use Pythagoras theorem?.



How precisely do you know your position and that of the stationary objects?
Unless you know them very precisely, any errors resulting from the assumption of a
flat plane will be small compared to the uncertainty of the positions themselves.


The accuracy level currently discussed is 15 meters without SA.



Do you need to calculate the actual distances from you to the objects, o
r do you (as you stated in your original post) only need to find the closest one?
If you need actual distances, then you will have to translate your latitude and
longitude coordinates into meters or kilometers or whatever, and that's slightly t
ricky because a degree of latitude always represents the same distance, but degrees
of longitude represent smaller and smaller distances as you move away from the equator in either direction.


I feel I have to do that , and with every received coordinates , while my vehicle is moving . I would require to approximat which object I am just approaching and passing away from it and then I need to interrogate only that object which is closest via RF link.


On the other hand, if you only need to find the closest object, and
don't care how far you actually are from it, then you don't have to
worry about any of that. Just pretend that a degree of latitude
is the same as a degree of longitude and calculate the "distances" in terms of degrees.
As for whether an 8-bitter can do this task, that depends mostly
on how often you need to update your estimate of the closest object.
I don't think you have mentioned that requirement yet.
As Christoph mentioned, it really would help if you could give a
complete description of the problem.


Language problem , here I think I have written enough English , but maybe not enough :) .
I would need to update every second my vehicle GPS coordinates , all other are stationary .
I have said earlier , my vehicle is moving , it searches the telemetry and list the received coordinates.
It then reads its own coordinates in real time , and it then has to calculate the approaching most nearby node the roadside out of all listed nodes. I feel I have explained my requirement here , if still I am not able to explain correctly please ask for clarification.

Best/
AP

Neil , the roads are 80- 100meter wide at most places and length is infinite all roads are interconnected :).






List of 32 messages in thread
TopicAuthorDate
Global positioning algorithm            01/01/70 00:00      
   Global?            01/01/70 00:00      
   Ehm what do you receive?            01/01/70 00:00      
      coordinates            01/01/70 00:00      
         Length/absolute value of a vector ?            01/01/70 00:00      
         How do they know?            01/01/70 00:00      
         An old greek...            01/01/70 00:00      
            What about doppler            01/01/70 00:00      
               not doppler & math            01/01/70 00:00      
                  Haversine formula is it accurate for short distanc            01/01/70 00:00      
               Are you thinking of D-VOR            01/01/70 00:00      
            An old greek... not accurate enough for            01/01/70 00:00      
               Well, you're stating that it's a 2D space.            01/01/70 00:00      
                  Well, you're stating that it's a 2D space.            01/01/70 00:00      
                     So how wide are your roads?!            01/01/70 00:00      
               You said approximate            01/01/70 00:00      
               Some questions            01/01/70 00:00      
                  Answers to Cooper            01/01/70 00:00      
                     Plane should be fine, then            01/01/70 00:00      
                        Plane should be fine, then            01/01/70 00:00      
                           If you have cartesian coordinates ...            01/01/70 00:00      
                           complex math trough LUT            01/01/70 00:00      
                              Fixed point            01/01/70 00:00      
                                 Scaling            01/01/70 00:00      
                     You have wide roads, then!            01/01/70 00:00      
                        That's still wide!            01/01/70 00:00      
                     Much better            01/01/70 00:00      
                         Much better            01/01/70 00:00      
                           Adjusting for latitude            01/01/70 00:00      
                              Thanks            01/01/70 00:00      
                  Not entirely true            01/01/70 00:00      
                     You\'re right            01/01/70 00:00      

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