??? 07/13/04 07:59 Read: times |
#74143 - RE: Snub diode Responding to: ???'s previous message |
hi,
...and the input is from a 2n2222a not the mcu output ...and it will not work with real 8051. How much current is defined for coil/"High Current" device? Let assume, it is about 1A. Typical hFE of BU807 is 100 at Ic=1A. Now 1A/100=10mA. It is minimum base current required for such conditions. But 10mA is quite big current for MCU pin. You know, standard 8051 output does not use strong pFET for continous sourcing. As result, MCU will not be able to open transistor. BTW, my tests show that 6k8 or above resistor should be used between MCU output pin and NPN transistor`s base if you need open it with high logical level. Another issue is that by such schematic you posted, transistor will be opened immediately at power-up (and any reset) time. It is because reset-defined pins` state is high level one. So, my suggestion: - use additional PNP transistor (for example, BC556) connected: MCU pin -> resistor 10k -> base of BC556; Vcc -> emitter of BC556; Collector of BC556 -> resistor 100E -> base of BU807. - or just use ULN2003 (upto 500mA). Regards, Oleg |
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Snub diode | 01/01/70 00:00 | |
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