| ??? 05/03/08 19:09 Read: times |
#154351 - Port 0 Pullups WHY??? Responding to: ???'s previous message |
But P0 is also use for accessing external address.. right..? Then P2 is also used for accessing an external address...
I have read Port 0 is used for accessing external mem location.. it has not got the pullup resistors.... Is it so??? For accessing external memory locations only very small current is required, so Port 0 does not have internal pull up resistors... right?... I have a doubt that even P2 is also used for External mem accessing.... But why P2 has got internal pullup resistors...????? If we are using P0 for data transfer we have to use a external pull up resistors.... to drive the current through Port 0 to the device...... correct???? Please reply..... |
| Topic | Author | Date |
| P0 pull up resistors | 01/01/70 00:00 | |
| ports structure | 01/01/70 00:00 | |
| More Port 0 history | 01/01/70 00:00 | |
| Of course, there is a reason for it... | 01/01/70 00:00 | |
| Port 0 Pullups WHY??? | 01/01/70 00:00 | |
| P0 is multiplexed for input/output; P2 is not | 01/01/70 00:00 | |
| This would all be perfectly obvious if only you\'d | 01/01/70 00:00 | |
| See this thread | 01/01/70 00:00 | |
| Scary Bible | 01/01/70 00:00 | |
| Only In Some Cases.... | 01/01/70 00:00 | |
| Directly connecting the base will hardly work! | 01/01/70 00:00 | |
| Hardly is correct.... | 01/01/70 00:00 | |
| what about a darlington? | 01/01/70 00:00 | |
| Will also turn off the weak pull-up... | 01/01/70 00:00 | |
| The high state is adequate for some things | 01/01/70 00:00 | |
OH | 01/01/70 00:00 |