| ??? 12/21/04 15:42 Read: times |
#83577 - Yes, negative logic! Responding to: ???'s previous message |
Andy said:
Surely, "Negative Logic" would mean that a low voltage level represents a '1', and a high represents '0'? Yes, what I said: "Negative Logic" would mean that a low voltage level represents a '1', means an 'active state'. 'Active state' in the application of Farshid means: 'Button pressed'. So, whenever he pushes a key he applies an 'active state' to according input, which he should do by applying a low voltage signal, due to the special port configuration of 'C51. Kai |
| Topic | Author | Date |
| invalid voltage on a pulled up/down Port | 01/01/70 00:00 | |
| replace s with c | 01/01/70 00:00 | |
| Thats not the solution. | 01/01/70 00:00 | |
| please follow the main problem | 01/01/70 00:00 | |
| and some news | 01/01/70 00:00 | |
| s51 is good | 01/01/70 00:00 | |
| Pullup/down | 01/01/70 00:00 | |
| Sorry for Echo. | 01/01/70 00:00 | |
| pull up/downs | 01/01/70 00:00 | |
| pullup+pulldown = potential-divider? | 01/01/70 00:00 | |
| Potential, potential divider? | 01/01/70 00:00 | |
| potential divider / where wires go | 01/01/70 00:00 | |
| blow it | 01/01/70 00:00 | |
| don't blowed it (atleast not untill now) | 01/01/70 00:00 | |
| where does the wires go | 01/01/70 00:00 | |
| To Erik and others | 01/01/70 00:00 | |
| This will not work with 'C51s | 01/01/70 00:00 | |
| Exactly | 01/01/70 00:00 | |
| just got the point :) | 01/01/70 00:00 | |
| And finally the problem solved! | 01/01/70 00:00 | |
| I meant ++hundreds of microampere++ | 01/01/70 00:00 | |
| Wrong question ! | 01/01/70 00:00 | |
| Negative Logic? | 01/01/70 00:00 | |
Yes, negative logic! | 01/01/70 00:00 |