| ??? 05/10/04 16:20 Read: times |
#70129 - ...Post No.3 Responding to: ???'s previous message |
When the above code was executed in the Windows 98 OS the result was as follows: 83331.85 83331.91 83331.91 83332.02 83332.02 83332.13 83332.13 83332.24 83332.24 83332.35 83332.35 83332.4 83332.4 83332.51 83332.51 83332.62 83332.62 83332.73 83332.73 83332.84 83332.84 83332.95 83332.95 83333.01 83333.01 83333.12 83333.12 83333.23 83333.23 83333.34 83333.34 83333.45 83333.45 83333.56 83333.56 83333.61 83333.61 83333.72 83333.72 83333.83 83333.83 83333.94 83333.94 83334.05 83334.05 83334.16 83334.16 83334.22 83334.22 83334.33 83334.33 83334.44 83334.44 83334.55 83334.55 83334.66 83334.66 83334.77 83334.77 83334.82 83334.82 83334.93 83334.93 83335.04 83335.04 83335.15 83335.15 83335.26 83335.26 83335.32 83335.32 83335.42 83335.42 83335.53 83335.53 83335.64 83335.64 83335.75 83335.75 83335.86 83335.86 83335.92 83335.92 83336.03 83336.03 83336.14 83336.14 83336.25 83336.25 83336.36 83336.36 83336.41 83336.41 83336.52 83336.52 83336.63 83336.63 83336.74 83336.74 83336.85 83336.85 83336.96 83336.96 83337.02 83337.02 83337.13 83337.13 83337.24 83337.24 83337.35 83337.35 83337.46 83337.46 83337.51 83337.51 83337.62 83337.62 83337.73 83337.73 83337.84 83337.84 83337.95 83337.95 83338.06 83338.06 83338.12 83338.12 83338.23 83338.23 83338.34 83338.34 83338.45 83338.45 83338.56 83338.56 83338.61 83338.61 83338.72 83338.72 83338.83 83338.83 83338.94 83338.94 83339.05 83339.05 83339.16 83339.16 83339.21 83339.21 83339.32 83339.32 83339.43 83339.43 83339.54 83339.54 83339.65 83339.65 83339.76 83339.76 83339.82 83339.82 83339.93 83339.93 83340.04 83340.04 83340.15 83340.15 83340.26 83340.26 83340.31 83340.31 83340.42 83340.42 83340.53 83340.53 83340.64 83340.64 83340.75 83340.75 83340.86 83340.86 83340.92 83340.92 83341.03 83341.03 83341.14 83341.14 83341.25 83341.25 83341.36 83341.36 83341.41 83341.41 83341.52 83341.52 83341.63 83341.63 83341.74 83341.74 83341.85 83341.85 Please note that the first 2 readings are of the first loop. i.e. difference between the first and the second reading is the time interval of the Sleep(100) of first execution of loop. The next 2 reading are for the second execution of the loop... and so on. Put it in MSExcel and work out the time (difference in 2 readings) of each execution loop. You will find that after every about 4~5 readings it will give a delay less than 100 msec. Continued on Post ...4 |
