Hi there,

Sorry for such a late response, i was trying other ways to solve my problem. anyhow thanx for cooeration. here i m providing with my display message routine, i have tried to comment it well to make it u ppl understand.

Once again thanx in advance.

Regards.

void DisplayMsg()
{
register unsigned char value, a, i, j, k;
register int xloc;
register unsigned int Address;
unsigned char v[18];
//Buffer to hold the string
register unsigned int Max, index;
MsgLength = GetLength();
//MsgLength is stored in eeprom, GetLength
//just reads two bytes of data from eeprom
Max = MsgLength - 16;
//Get String Now
Address = 2;
//starting address of message in eeprom
ReadText(Address, 16);
//reads 16 bytes of data from the Address
//through the eeprom
Address = 18;
//Address is now 18
for(index = 0; index < Max; index++, Address++)
//this is main loop to display the full
//message upto Max
{
for(j = 0; j < 15; j++)
RText[j] = RText[j + 1];
//shift one char to left
RText[j] = ReadChar(Address);
//Read Next Char to add to message
for(xloc = 0; xloc >= -5; xloc--)
//this loop is used for scrolling,
//one coloumn is to be skipped each
//time.
{
for(i = 7; i > 0; i--)
//7 rows
{
if(i < 7)
{
Delay();
Delay();
}
else
Delay();

for(j = 0; j < 16; j++)
v[j] = CharSet[RText[j] - 32][i - 1];
//CharSet is text display format, saved
//in code memory, it takes time to read
//therefore used as delay

for(j = 15; j > 0; j--)
{
value = v[j];
for(k = 6; k > 0; k--)
//output binary data
{
xd = value & 1;
xc = 1; //reset clk xc = 0;
value >>= 1;
}
}//end for j
a = 6 + xloc; /*Last Character*/
value = v[j];
for(k = a; k > 0; k--)
//output binary data
{
xd = value & 1;
xc = 1; //reset clk
xc = 0;
value >>= 1;
}
if(bF1 || bF3 || bResetEnglish || bResetGraphics) return;
//booleans when needed, exit from this
//function
ResetY(i - 1);
st = 1; st = 0;
//Reset Strobe
}//end for i
Delay();
Delay();
//Delay b4 exiting function, 4 last row display
}//end for xloc
}//end for index
}//end void DisplayEnglish()