Hi All,

The archive Oleg has told has lot of information. i have read the complete thread. but according to following thread:

http://www.8052.com/forum/read.phtml?id=76480

Okay, let assume you calculated that refresh routine takes 100ìs.

My refresh routine when calculated, completes in atleast 2000ìs. Can anyone help me to enhance this routine. I am giving my display routine code:

void DisplayMsg()
{
unsigned char value, j, k, a;
short xloc, i;
unsigned int Address;
unsigned int Max, index;
MsgLength = GetLength();
Max = MsgLength - 16;
//Get String Now
Address = 2;
ReadText(Address, 16);
Address = 18;
for(index = 0; index < Max; index++, Address++)
{
for(j = 0; j < 15; j++)
RText[j] = RText[j + 1]; //shift one char to left
RText[j] = ReadChar(Address); //Read Next Char to add to message
for(xloc = 0; xloc >= -5; xloc--)
{
for(i = 6; i >= 0; i--)
{
for(j = 15; j > 0; j--)
{
value = CharSet[RText[j] - 32][i];
for(k = 6; k > 0; k--) //output binary data
{
xd = value & 1;
xc = 1; //reset clk
xc = 0;
value >>= 1;
}
}//end for index
value = CharSet[RText[j] - 32][i];
for(k = 6 + xloc; k > 0; k--) //output binary data
{
xd = value & 1;
xc = 1; //reset clk
xc = 0;
value >>= 1;
}
// if(bF1 | bReset) return;
Set_y_data(ydata[i]);
st = 1; st = 0;
}//end for i
}//end for xloc
}//end for index
}//end void DisplayMsg()


here, CharSet[] is the character set we have to display, this is in code memory, ReadText() reads data from EEPRom, i have used AT24C64 to store data.

Actually the most of the time is taken by for(j = 15; ...), this is because we have to shift 90 bits per row in every case.

Regards,
Farrukh Lodhi