??? 06/22/05 12:31 Read: times |
#95578 - based on the above Responding to: ???'s previous message |
is it possible to solving this problem with a software method
the answer may be yes if you have while (pin); instead of for (timeout = nnn; timeout !=0; timeout--) { if (pin) { break; } } if (!pin) { error(); } you are, indeed asking for punishment. Erik |