??? 02/28/07 15:15 Read: times |
#133938 - another question Responding to: ???'s previous message |
Mike Stegmaier said:
The nop adjusts the binary code for the jbc instruction. Without it, I would have to use more logic gates to decode it.
The last paremeter in the jbc is dependent on how far the label is away from the instruction. Also, if I wanted to, I could replace NOP with any other 1-byte instruction without affecting my code. One more question from an ignorant person: what about the interrupt/reset vectors? rgds Patrick |