??? 06/19/08 19:03 Read: times Msg Score: +1 +1 Good Answer/Helpful |
#156046 - don't use a resistor in the GND connection Responding to: ???'s previous message |
unless you have a very good reason.
What does a resistor in the GND connection mean? Let both outputs T1OUT and T2OUT be on -10V and R1OUT be at 0V and R2OUT be at 5V and R1OUT being connected to RX of an 8051. Now switch both T1OUT and T2OUT to +10V (against a resistive or capacitive load). The current needed to drive both lines will cause a voltage drop over your resistor in the GND connection. This very voltage drop will cause a lower potential for R2OUT (where it does not hurt) and a lower potential for R1OUT (where it does hurt). Essentially you are feeding (part of) the two output driver currents into the protection diodes of a single 8051 input. Plus the rationale "lower the noise" is only partly met: you'll find part of the switching noise on R1OUT and R2OUT (which typically are connected to the heart of your circuit). Likewise you'll find part of (external) noise applied on T1OUT and T2OUT to propagate on R1OUT and R2OUT. (ESD not yet mentioned) In short: don't use a resistor in the GND connection unless you have a very good reason. |